http://jackxiang.com/index.php zh-cn http://jackxiang.com/post// jack <xdy108@126.com> Tue, 23 Aug 2011 04:27:55 +0000 http://jackxiang.com/post// echo "12345"|rev
root@116.255.139.240:~# echo "12345"|rev 54321

其次可以自己编写纯bash脚本来实现
脚本 rev.sh 内容如下
#!/bin/bash str=$1; len=${#str}; for((i=len;i>-1;i--)) do echo -n "${str:i:1}" done echo
命令行: bash rev.sh "想反序的字符串"
root@116.255.139.240:~# sh shell.sh jackxiang gnaixkcaj

源代码在:
http://www.zhangyan.name/fbtopic.php?fid=24
参考资料：http://www.zhangyan.name/fbtopic.php?fid=24
http://zhidao.baidu.com/question/99724148.html ]]> http://jackxiang.com/post//#blogcomment <user@domain.com> Thu, 01 Jan 1970 00:00:00 +0000 http://jackxiang.com/post//#blogcomment