标题：[实践OK]python获取传入argv参数列表，以及字符为空判断，python退出之退出os._exit(-1)。
出处：向东博客 专注WEB应用 构架之美 --- 构架之美，在于尽态极妍 | 应用之美，在于药到病除
时间：Tue, 23 Feb 2021 17:43:57 +0000
作者：jackxiang
地址：https://jackxiang.com/post/10869/

内容：

#coding=utf-8
import sys
import os
import xlrd  # 导入库

for i in range(len(sys.argv)):
    print ("sys.argv[%d] = %s" % (i, sys.argv[i]))


python excelsearchKeyList.py k.txt
sys.argv[0] = excelsearchKeyList.py
sys.argv[1] = k.txt

二）判断字符为空：

#coding=utf-8
import sys
import os
import xlrd  # 导入库
# 打开文件
if len(sys.argv) >= 2: 
  file = open(sys.argv[1])
  # file = open("/Users/jackXiang/pylearning/k.txt")
else: 
  file = open("/Users/jackXiang/pylearning/cctvhyjykeywordslist.txt")

for line in file:
      line = line.replace('\r','').replace('\n','').replace('\t','')
      if line.strip()=='':
        print ('line is null')
      else:
        print(line)



python excelsearchKeyList.py  k.txt
原创视频
line is null
line is null



三）判断是否传入新的参数：

# 打开文件
if len(sys.argv) >= 2: 
  print(sys.argv[1])
  file = open(sys.argv[1])
else: 
  file = open("/Users/jackXiang/pylearning/cctvhyjykeywordslist.txt")
for line in file:
      print(line)

os._exit(-1)
# os._exit(-1)
sys.exit()


来自：https://blog.csdn.net/index20001/article/details/74294945#:~:text=Python%E7%A8%8B%E5%BA%8F%E6%9C%89%E4%B8%A4%E7%A7%8D,%E8%A7%A3%E9%87%8A%E5%99%A8%E5%B0%86%E4%BC%9A%E9%80%80%E5%87%BA%E3%80%82


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